Volume And Surface Area For Aptitude question

1. formula for cube

एक Cube = 'a' इकाई का किनारा दें, फिर

volume and surface area

2. formula for cuboid

लंबाई = l इकाई, चौड़ाई = b इकाई और ऊँचाई = h इकाई दें। फिर
$$\begin{array}{c}\text{(a) Volume of Cuboid}\\ =(l\ast b\ast h)\text{cubic units}\\ \\ \end{array}$$

$$\begin{array}{c}\text{(b) Surface Area of Cuboid}\\ =2(lb+bh+hl)\text{sq. units}\end{array}$$

$$\begin{array}{c}\\ \\ \text{(c) Diagonal of Cuboid}\\ =\sqrt{l^2+b^2+h^2}units\end{array}$$

3. formula for sphere

 क्षेत्र के त्रिज्या = r इकाई, तो
$$\begin{array}{c}\text{(a) Volume of Sphere}\\ =\left(\frac{4}{3}\pi r^3\right)\text{cubic units}\end{array}$$

$$\begin{array}{c}\\ \\ \text{(b) Surface Area of Sphere}\\ =\left(4\pi r^2\right)\text{sq. units}\end{array}$$

4. formula for Hemisphere

 क्षेत्र के त्रिज्या = r  इकाई, तो
$$\begin{array}{c}\text{(a) Volume of Hemisphere}\\ =\left(\frac{2}{3}\pi r^3\right)\text{cubic units}\end{array}$$

$$\begin{array}{c}\\ \\ \text{(b) Curved Surface Area of Hemisphere}\\ =\left(\frac{2}{\pi }{r}^2\right)\text{sq. units}\end{array}$$

$$\begin{array}{c}\\ \\ \text{(c) Total Surface Area of Hemisphere}\\ =\left(3\pi r^2\right)\text{sq. units}\end{array}$$

5. formula for cone

 आधार की त्रिज्या = r इकाई और शंकु की ऊँचाई = h इकाई दें। फिर,
$$\begin{array}{c}\text{(a) Slant Height of Cone, l}\\ =\sqrt{r^2+h^2}units\\ \\ \end{array}$$

$$\begin{array}{c}\text{(b) Volume of Cone}\\ =\left(\frac{1}{3}\pi r^{2}h\right)\text{cubic units}\\ \\ \end{array}$$

$$\begin{array}{c}\text{(c) Curved Surface Area of Cone}\\ =\left(\pi rl\right)\text{sq. units}\\ \\ \end{array}$$

$$\begin{array}{c}\text{Total Surface Area of Cone}\\ =(\pi rl+\pi r^2)\text{sq. units}\end{array}$$

6. formula for cylinder

आधार की त्रिज्या = r इकाई और सिलेंडर की ऊँचाई = h इकाई दें। फिर,

$$\begin{array}{c}\text{(a) Volume of Cylinder}\\ =\left(\pi r^{2}h\right)\text{cubic units}\end{array}$$

$$\begin{array}{c}\\ \\ \text{(b) Curved Surface Area of Cylinder}\\ =\left(2\pi rh\right)\text{sq. units}\end{array}$$

$$\begin{array}{c}\\ \\ \text{(c) Total Surface Area of Cylinder}\\ =(2\pi rh+2\pi r^2)\text{sq. units}\\ =2\pi r(h+r)\text{sq. units}\end{array}$$